# Line slope calculator x+8y=48

**Straight line given by points A[0; 6] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.125x+6

**Canonical form of the line equation:**x+8y-48 = 0

**Parametric form of the line equation:**

x = 8t

y = -t+6 ; t ∈ R

**Slope:**m = -0.125

**Slope angle of line: φ =**-7°7'30″ = -0.1244 rad

**X intercept:**x

_{0}= 48

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 5.9537

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; -1)

**Normal vector: n =**(1; 8)

**Midpoint of the segment AB: M =**[4; 5.5]

**Perpendicular Bisector equation:**8x-y-26.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 57°59'41″ = 1.0122 rad**