# Line slope calculator 4x+y=12

**Straight line given by points A[1; 8] and B[2; 4]**

## Calculation:

**Slope-intercept form of line:**y = -4x+12

**Canonical form of the line equation:**4x+y-12 = 0

**Parametric form of the line equation:**

x = t+1

y = -4t+8 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = 12

**Distance line from the origin:**d

_{0}= 2.9104

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[1.5; 6]

**Perpendicular Bisector equation:**x-4y+22.5 = 0

**Vector OA = (1; 8) ; |OA| = 8.0623**

**Vector OB = (2; 4) ; |OB| = 4.4721**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 19°26'24″ = 0.3393 rad**